All categories

2 years ago

Solve for X 121 +7< -11 OR 5x- 8 > 40

Mathematics

1 answer:

Trava [24]2 years ago

3 0

Answer:

x > 48/5 the first one is false

You might be interested in

-5 / 6 - 1 / x equals negative two thirds

anyanavicka [17]

$x = - 6$

I think it's help

6 0

3 years ago

A cylinder has a diameter of 14 cm and a volume of 112 pi.

vekshin1

Height of cylinder is 2.285 centimeters

Diameter = 14 cm
Radius = 7 cm (14/2)
Volume = 112 pi

Volume of cylinder = pi(radius)^2 h
112pi = pi(7)^2 h
Divide both sides
112 = 49 h
h = 112/49
h = 2.285 centimeters

8 0

2 years ago

The quotient of the division 2223÷57 is

Katarina [22]

Answer:

Kkkkkkkkkkkmmmmmmm

7 0

3 years ago

Read 2 more answers

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago

Select all of the following that are quadratic equations.

Lelechka [254]

Answer:

3x ^2 + 5x - 7 = 0

5x ^2+ 15x = 0

x ^2 - 4x = 4x + 7

Step-by-step explanation:

Just find a equation with a degree of 2 and boosh

6 0

2 years ago