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4 years ago

Help and explain pllzz asap

Mathematics

2 answers:

Mnenie [13.5K]4 years ago

8 0

T is greater than -15 because numbers after -15, like -16... are less than -15, so when its decreasing it gets lower. Since the questions says the temp stayed above -15, that means the temp could be -14...-13 and so on.

dexar [7]4 years ago

3 0

Okay so you can use the variable "T" for temp, so T stayed above, meaning higher than, -15
to convert this to an equation, use the greater than sign (<span>>)

so it's like this

</span>T <span>> -15</span>

You might be interested in

T is the midpoint of KL. K has coordinates (2,−6), and T has coordinates (−4,2). Identify the coordinates of L.

kotykmax [81]

Answer:

$L = (-10,10)$

Step-by-step explanation:

Given

$K = (2,-6)$

$T = (-4,2)$

Required

Determine the coordinates of L

Since T is the midpoint of K and L, we make use of:

$T_x = \frac{K_x + L_x}{2}$

and

$T_y = \frac{K_y + L_y}{2}$

Solving for $L_x$

$T_x = \frac{K_x + L_x}{2}$

$-4 = \frac{2 + L_x}{2}$

Multiply through by 2

$-8 = 2 + L_x$

$L_x = -8 - 2$

$L_x = -10$

Solving for $L_y$

$T_y = \frac{K_y + L_y}{2}$

$2 = \frac{-6+L_y}{2}$

Multiply through by 2

$4 = -6 + L_y$

$L_y = 4 + 6$

$L_y = 10$

Hence: The coordinates of L is:

$L = (-10,10)$

6 0

3 years ago

Please help solve this and show work

Dafna11 [192]

Answer: x=9

Step-by-step explanation:

7x+43=106

subtract 43 from both sides

7x=63

divide by 7

x=9

8 0

3 years ago

Pls help fast 10 points instead of 5

Elodia [21]

Stop capping its 5 points

4 0

3 years ago

What is th result of converting 20 ounces into pounds?

Harrizon [31]

Hello!

The Correct Answer would be:

"1.25 Pounds"

Why? Well:

1 ounce (oz) is equal to 0.0625 pounds (lb).

1 oz = (1/16) lb = 0.0625 lb

The mass m in pounds (lb) is equal to the mass m in ounces (oz) divided by 16:

m(lb) = m(oz) / 16

So as Result, The Answer is 1.25 Pounds.

Hope this Helps! Have A Wonderful Day! :)

6 0

3 years ago

Read 2 more answers

A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i

garri49 [273]

Answer:

The degrees of freedom first given by:

$df=n-1=12-1=11$

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :

Null hypothesis: $\mu \leq 5$

Alternative hypothesis: $\mu > 5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The degrees of freedom first given by:

$df=n-1=12-1=11$

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0

4 years ago