Answer:
0 I think??
Step-by-step explanation:




Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.
Step-by-step explanation:
For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.
in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.
Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.
Two triangles in sphere that are similar must be congruent.
Answer:
The area is 45 units squared
Step-by-step explanation:
If the rectangle's width is 3 units, and the length is 5 times then:
5 x 3 = 15
So the length is 15 units
The area is length times width
15 x 3 = 45
The area is 45 units squared
Answer:
80.0456<
<81.1210
Step-by-step explanation:
-Given the mean,
and
, the confidence interval can be calculated using the formula:

#We substitute our values in the formula to solve for CI:
![=\bar x\pm z\times \frac{\sigma}{\sqrt{n}}\\\\=\bar y\pm z_{0.05}\times \frac{s}{\sqrt{72}}\\\\=80.5833\pm 1.645\times \frac{2.77369}{\sqrt{72}}\\\\=80.5833\pm0.5377\\\\=[80.0456,81.1210]](https://tex.z-dn.net/?f=%3D%5Cbar%20x%5Cpm%20z%5Ctimes%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C%3D%5Cbar%20y%5Cpm%20z_%7B0.05%7D%5Ctimes%20%5Cfrac%7Bs%7D%7B%5Csqrt%7B72%7D%7D%5C%5C%5C%5C%3D80.5833%5Cpm%201.645%5Ctimes%20%5Cfrac%7B2.77369%7D%7B%5Csqrt%7B72%7D%7D%5C%5C%5C%5C%3D80.5833%5Cpm0.5377%5C%5C%5C%5C%3D%5B80.0456%2C81.1210%5D)
Hence, the confidence interval lies between 80.0456 and 81.1210
Answer:
5/6 a pan of brownies.
Step-by-step explanation:
2 1/2=5/2, So you have 5/2 pans of brownies. If your sister eats 1/3 of these brownies we can write the equation 5/2*1/3=b=5/6, with variable b being how much of a pan of brownies your sister has eaten. Your sister has eaten 5/6 a pan of brownies.