Find the positive integer n for which 98! x 9900 = n!

If a is negative, then is negative.

Leviafan [203]

A negative and a negative is a positive and a negative is a negative

7 0

3 years ago

FIND THE MISSING DIMENSION! NEED ASAP! TINY SQUARE IS A =3025 in ²

Nata [24]

Answer:

Step-by-step explanation:

Rule: never completely trust a diagram that comes with a geometry question. This is a case in point. The "tiny" square is actually much larger than the "larger" square.

If you are trying to find the length of the sides of the squares, the formula is

Area = side^2

3025 = side^2

Take the square root of both sides.

sqrt(3025) = sqrt(side^2)

To find the square root of 3025, do the following

Press √

type in 3025

type in =

You should get 55.

======================

The second square is done the same way

√

90.75

=

And you should get 9.526

4 0

3 years ago

PLEASE HELP WILL GIVE POINTS ABD BRAINLYIST ASAP

fiasKO [112]

Answer:

6

Step-by-step explanation:

2.5x6=15 and thats the closest it'll get. To be exact, it's 6.2, but i dont know if you need that.

8 0

2 years ago

Read 2 more answers

You have a square that has a side length of $1$ centimeter. Each minute, $2$ centimeters are added to the side length. After $10

Mariulka [41]

Answer:

Difference in area of the last square and the initial square = 440 cm²

Step-by-step explanation:

Length of the side of a square = 1 cm

Area of the square = (side)² = 1 cm²

Addition of side length every minute = 2 cm

After x minutes length of each side of the square = (1 + 2x) cm

If x = 10 minutes

Length of each side of the square = [1 + 2(10)]

= 21 cm

Area of the square after 10 minutes = (21)²

= 441 cm²

Therefore, difference in area of the last square and area of the initial square

= 441 - 1

= 440 cm²

5 0

2 years ago

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0

2 years ago