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Tanzania [10]
3 years ago
9

What is the answer to 7(2x + 9)

Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

14x + 63

Step-by-step explanation:

7(2x+9)\\\\14x+63\\\\\left \{ {{7*2x=14x} \atop {7*9=63}} \right.

Hope this helps.

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Guys help me on this one please…
Ann [662]

Answer: 6. 35 hours

7. 741 Miles

8. 1.5 or 1.54

Step-by-step explanation:

6. 142.20/6=23.7

829.50/23.7=35

7. 117/3=39

39x19=741

8.19/12.35=1.538

5 0
2 years ago
Find the length of x. Assume the triangles are similar.
Veronika [31]

Answer:

  x = 32

Step-by-step explanation:

The longest side is double the length of the shortest side, so x is 2·16 = 32.

6 0
3 years ago
A local video store has two new renting plans. Plan A charges a $10 monthly fee and $2 for every movie rented. Plan B charges $4
Margaret [11]

Answer:

18 or 17

Step-by-step explanation:

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5 0
2 years ago
Write an inequality the score in a basketball game is greater than or equal to 10 points
andreev551 [17]
S greater than or equal to 10
4 0
3 years ago
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
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