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Juli2301 [7.4K]

2 years ago

14

HELPPP DUE IN 8 MINS!! There are many cylinders with a height of 9 inches. Let r represent the radius in inches and V represent

the volume in cubic inches. Is there a linear relationship between the radius and the volume of
these cylinders?

2 answers:

skelet666 [1.2K]2 years ago

4 0

Answer:

It's either 4 or 9

Step-by-step explanation:

Yes, there is.

Zolol [24]2 years ago

3 0

Answer:

I believe its 3

Step-by-step explanation:

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10 identical spheres of radius 7cm are to be painted. What is the total area of surface to be painted

IgorLugansk [536]

Answer:

Surface area = 4 π r2 square units

Step-by-step explanation:

6 0

2 years ago

Which ordered pair is NOT included in a graph of y=x+5?

belka [17]

I need the picture to answer it

7 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

The coordinates of each rectangle ABCD are A (0,2) B (2,4) C (3,3) D (1,1). Find the distance of each side of the rectangle then

EastWind [94]

AB = CD = √8 ≈ 2.8 units

BC = AD = √2 ≈ 1.4 units

Area of the rectangle ABCD = 3.92 units²

Perimeter of the rectangle ABCD = 8.4 units

<h3>How to Find the Area and Perimeter of a Rectangle?</h3>

Given the coordinates of vertices of rectangle ABCD as:

A(0,2)
B(2,4)
C(3,3)
D(1,1)

To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.

Using the distance formula, we have the following:

AB = √[(2−0)² + (4−2)²]

AB = √[(2)² + (2)²]

AB = √8 ≈ 2.8 units

CD = √8 ≈ 2.8 units

BC = √[(2−3)² + (4−3)²]

BC = √[(−1)² + (1)²]

BC = √2 ≈ 1.4 units

AD = √2 ≈ 1.4 units

Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²

Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units

Learn more about the area and perimeter of rectangle on:

brainly.com/question/24571594

#SPJ1

5 0

6 months ago

Someone help please need it asapp

mojhsa [17]

The answer is f(-2)=g(-2

4 0

2 years ago