Answer:
The answer is 5.5, 6.0 and 8.0
T = 5 a
i = 4% aa
j = 1200
c = ...
j = cit/100
c = 100j / it
c = 100*1200 / 4*5
c = 120000 / 20
c = 12000/2
c = 6000
montante
M = c+j
M = 6000+1200
M = 7200
Answer:
t ≥ 18
Step-by-step explanation:
He has run 12 miles plus some more miles t. He need to run at least 30 miles
12+t ≥ 30
Subtract 12 from each side
12+t-12 ≥ 30-12
t ≥ 18
Using the clustering estimation technique the approximate total weight oranges is 35 ounces.
The intersection is at (2,-1)