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2 years ago

Solve by using the quadratic formula: Simplify

Mathematics

2 answers:

larisa [96]2 years ago

8 0

Answer:

-6 - square root 31, -6 + square root 31

almond37 [142]2 years ago

3 0

Answer:

x = $\frac{48 - \sqrt{1984} }{-8}$

x = $\frac{48 + \sqrt{1984} }{-8}$

Step-by-step explanation:

-4 $x^{2}$ - 48x - 20 = 0

Remember, the quadratic formula is:

x = $\frac{-b +- \sqrt{b^{2} -4ac } }{2a}$

A quardatic equation in standard form is;

a $x^{2}$ + bx + c

Substitute in the values and solve;

$\frac{48 +- \sqrt{(-48)^2 - 4 * (-4) * (-20)} }{2*(-4)}$

Simplify;

$\frac{48 +-\sqrt{2304 -320} }{-8}$

x = $\frac{48 +- \sqrt{1984} }{-8}$

x = $\frac{48 - \sqrt{1984} }{-8}$

x = $\frac{48 + \sqrt{1984} }{-8}$

You might be interested in

If bcd~gef find value of x

ddd [48]

Answer:

$x = 13$

Step-by-step explanation:

Given

See attachment

Required

Find x

From the attachment, we have:

$BC = x + 4$

$BD = 2x - 7$

$GE = 51$

$GF = 57$

Because both triangles are similar, we use the following equivalent ratios:

$BC : BD = GE : GF$

Substitute values for each parameter

$x + 4 : 2x- 7 = 51 : 57$

Convert to fractions

$\frac{x + 4}{2x- 7} = \frac{51 }{ 57}$

Simplify the right-hand side

$\frac{x + 4}{2x- 7} = \frac{17}{19}$

Cross Multiply

$19(x + 4) = 17(2x - 7)$

$19x + 76 = 34x - 119$

Collect Like Terms

$19x - 34x = -76 - 119$

$-15x = -195$

Solve for x

$x = \frac{-195}{-15}$

$x = 13$

3 0

3 years ago

Find an equivalent system of equations for the following system:<br> 2x + 4y = 4<br> -5x + 5y = 5

tamaranim1 [39]

Answer:

x+2y=2

-1x+1y=5

Step-by-step explanation:

Any system whose equations have the following characteristic

x+2y=2

-1x+1y=1

Is equivalent to the original system, since the differ in a number, the first equation is divided by 2 and the second by 5, we can say any system is equivalent to the original when it is escalated by a factor between its functions.

5 0

3 years ago

Read 2 more answers

Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8

Blababa [14]

$w(s,t)=f(u(s,t),v(s,t))$

From the given set of conditions, it's likely that you are asked to find the values of $\dfrac{\partial w}{\partial s}$ and $\dfrac{\partial w}{\partial t}$ at the point $(s,t)=(1,0)$ .

By the chain rule, the partial derivative with respect to $s$ is

$\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}$

and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21$

Similarly, the partial derivative with respect to $t$ would be found via

$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5$

6 0

3 years ago

Help please!<br>Find the surface area of a cube with sides and height of 10 inches

juin [17]

Answer:

600

Step-by-step explanation:

10 times 10 is 100. A cube has 6 sides. 6 times 100 is 600

8 0

3 years ago

Read 2 more answers

3.321 divided by 0.07