<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%20%7B%7D%5E%7B2%7D%20%20-%205" id="TexFormula1" title="f(x) = x {}^{2}

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3 years ago

" alt="f(x) = x {}^{2} - 5" align="absmiddle" class="latex-formula">
what is the vertex and the equation for the axis of symmetry

Mathematics

1 answer:

faust18 [17]3 years ago

7 0

Answer:

The vertex is (0, -5) and the axis of symmetry is x = 0.

Step-by-step explanation:

In order to find the axis of symmetry, we look for the x value of the vertex. We can find this using the equation -b/2a, in which a is equal to the coefficient of the x^2 term and b is the coefficient of the x term.

x = -b/2a

x = 0/2(1)

x = 0/2

x = 0

So the axis of symmetry is 0 as is the x value of the vertex. Now we can find the y value by plugging in the x value into the equation.

f(x) = x^2 - 5

f(x) = 0^2 - 5

f(x) = 0 -5

f(x) = -5

This gives us a vertex of (0,-5)

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