Question

A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes

Answer 1

Complete question is;

A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes.

a. What equation can you use to find the distance of the flowerbed from the hive?

b. How far is the flowerbed from the hive?

Answer:

A) (d/9) + 900 + (d/6) = 1080

B) d = 648 ft

Step-by-step explanation:

A) We are told that A bee flies at 9 feet per second directly to a flower bed from its hive.

Time taken is given as;

t = distance/speed

If distance is d from the hive to the flower bird.

Then, t1 = d/9

The bee stays at the flowerbed for 15 minutes. Thus, time spent at the flowerbird in seconds is; t2 = 15 × 60 = 900 seconds.

We are told that the bee flew directly back to the hive at 6 feet per second.

Thus,time is;

t3 = d/6

Since total time spent away from hive is 18 minutes, then converting to seconds, we have; t = 18 × 60 = 1080 s

Thus;

(d/9) + 900 + (d/6) = 1080

B) Since we have derived;

(d/9) + 900 + (d/6) = 1080

Then we can find d.

Multiply through by 18 to get;

2d + (900 × 18) + 3d = 1080 × 18

2d + 16200 + 3d = 19440

5d = 19440 - 16200

5d = 3240

d = 3240/5

d = 648 ft