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Trava [24]
3 years ago
15

What is 3 log Subscript 2 Baseline x minus (log Subscript 2 Baseline 3 minus log Subscript 2 Baseline (x + 4)) written as a sing

le logarithm?
Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

A.

Step-by-step explanation:

Serhud [2]3 years ago
3 0

Answer:

\log_{2} [\frac{x^{3}(x + 4)}{3}]

Step-by-step explanation:

We have to write the following logarithmic expression as a single logarithm.

The given expression is

3\log_{2} x - [\log_{2} 3 - \log_{2}(x + 4)]

= 3\log_{2} x - \log_{2} (\frac{3}{x + 4})

{Since, \log A - \log B = \log \frac{A}{B}, from the properties of logarithmic function }

= \log_{2} x^{3}  - \log_{2} (\frac{3}{x + 4})

{Since, a\log b = \log b^{a}, which also a logarithmic property}

= \log_{2} [\frac{x^{3}}{\frac{3}{x + 4}}]

= \log_{2} [\frac{x^{3}(x + 4)}{3}] (Answer)

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Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. T
gayaneshka [121]

Answer:

a) Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

b) t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

Step-by-step explanation:

Information given

\bar X=2.8 represent the sample mean

s=2.6 represent the population standard deviation  

n=1310 sample size  

\mu_o =3 represent the value to test

\alpha=0.5 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

Part b

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

6 0
3 years ago
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