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Trava [24]
3 years ago
15

What is 3 log Subscript 2 Baseline x minus (log Subscript 2 Baseline 3 minus log Subscript 2 Baseline (x + 4)) written as a sing

le logarithm?
Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0

Answer:

A.

Step-by-step explanation:

Serhud [2]3 years ago
3 0

Answer:

\log_{2} [\frac{x^{3}(x + 4)}{3}]

Step-by-step explanation:

We have to write the following logarithmic expression as a single logarithm.

The given expression is

3\log_{2} x - [\log_{2} 3 - \log_{2}(x + 4)]

= 3\log_{2} x - \log_{2} (\frac{3}{x + 4})

{Since, \log A - \log B = \log \frac{A}{B}, from the properties of logarithmic function }

= \log_{2} x^{3}  - \log_{2} (\frac{3}{x + 4})

{Since, a\log b = \log b^{a}, which also a logarithmic property}

= \log_{2} [\frac{x^{3}}{\frac{3}{x + 4}}]

= \log_{2} [\frac{x^{3}(x + 4)}{3}] (Answer)

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The equal distance between 0 and 1 must be one-half or 1/2.

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a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

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