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suter [353]
2 years ago
11

Please answer with steps

Mathematics
2 answers:
lidiya [134]2 years ago
6 0

Answer:

9 litres

Step-by-step explanation:

the volume (V) of the tank is calculated as

V = lbh ( l is length, b is breadth , h is height )

here l = 60 cm, b = 15 cm, h = 10 cm , then

V = 60 × 15 × 10 = 9000 cm³

using the conversion 1 litre = 1000 cm³ , then

V = 9000 ÷ 1000 = 9 litres

oee [108]2 years ago
4 0

Answer:

  9 liters

Step-by-step explanation:

It is often convenient to make use of the fact that 1 liter is 1000 cm³, or 1 dm³, where 1 dm = 10 cm. Expressing the tank dimensions in decimeters, we see they are ...

  L = 6 dm, W = 1.5 dm, H = 1.0 dm

Then the volume is ...

  V = LWH

  V = (6 dm)(1.5 dm)(1.0 dm) = 9.0 dm³ = 9 L

9 liters of water are needed to fill the empty tank.

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Answer:

(x − 2 + 2i)(x − 2 − 2i) in standard form

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3 years ago
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Mazyrski [523]

Answer:

8. une ceinture   9. une jupe i think    10. un pull      11. casquette

Step-by-step explanation:

<u>For 9:</u>

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Which number is a solution of the inequality? 3x – 7 &gt; – 1 A. 0 B. 2 C. 5
Softa [21]

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C. 5

Step-by-step explanation:

3x – 7 > – 1

Add 7 to each side

3x – 7+7 > – 1+7

3x> 6

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5 0
3 years ago
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1469.52 round to the nearest tenths place
Brrunno [24]

Answer:

1469.5

Step-by-step explanation:

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8 0
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Can someone plz help me with 11,12,13 plz show work
dimaraw [331]

Answer:

  11.  x = -3+√37 ≈ 3.08276

  12.  x = 11.2

  13.  x = -6 +6√5 ≈ 7.41641

Step-by-step explanation:

In each case, the relation of interest is ...

  (distance to circle near) × (distance to circle far) = (distance to circle near) × (distance to circle far)

When there is only one point of intersection of the secant with the circle—because it is a tangent—then the product is the square of the length of the tangent.

11. 2(2+12) = x(x +6)

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12. 5(5+x) = 9(9)

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13. x(x +12) = 12(12)

  x² +12x -144 = 0

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  x = -6 +√180 ≈ 7.41641

_____

<em>Comment on this secant rule</em>

This rule turns out to apply whether the point of intersection of the secant lines is outside the circle (as in these problems) or inside the circle (as in problem 9). The product of the two distances from the point of intersection to the circle is a constant for a given pair of intersecting secants/chords.

6 0
3 years ago
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