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3 years ago

14

Which two integers is V 194 between?

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

the integer in question lies between 13 and 14.

Step-by-step explanation:

Review the perfect squares in the neighborhood of 194. The first that came to my mind was 225 (the squre of 15), and then 196 (the square of 14), and then 169, the square of 13.

Since 169 < x^2 < 196, the integer in question lies between 13 and 14.

Check with a calculator: √194 ≈ 13.93

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37.26 m +2.7 m + 0.0015=

Stells [14]

Add the two values being multiplied by m
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3 years ago

-3/5m + 8 = 20<br> what is the answer of m

horrorfan [7]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

$\qquad \sf \dashrightarrow \: - \frac{ 3}{5} m + 8 = 20$

$\qquad \sf \dashrightarrow \: - \frac{ 3}{5} m = 20 - 8$

$\qquad \sf \dashrightarrow \: - \frac{ 3}{5} m =12$

$\qquad \sf \dashrightarrow \: - \frac{ }{} m =12 \times \frac{5}{3}$

$\qquad \sf \dashrightarrow \: - m = 4 \times 5$

$\qquad \sf \dashrightarrow \:m = - 20$

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2 years ago

Which expression uses the associative property to make it easier to evalute?

mixas84 [53]

Answer:

The correct option is (c).

Step-by-step explanation:

The given expression is :

$14(\dfrac{3}{2}\times \dfrac{1}{4})$

We need to use the associative property to make it easier.

The associative property for multiplication is as follows :

$A\times (B\times C)=(A\times B)\times C$

We have,

$A=14, B=\dfrac{3}{2}\ and\ C=\dfrac{1}{4}$

$14(\dfrac{3}{2}\times \dfrac{1}{4})=(14\times \dfrac{3}{2})\times \dfrac{1}{4}$

Hence, the correct option is (c).

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3 years ago

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GuDViN [60]

-2x and 4x
and x2 so tats it

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3 years ago

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Gnoma [55]

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5 out of 20 = 1 out of 4

1/3 is larger that 1/4
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2 years ago