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Vlad1618 [11]
3 years ago
14

Which two integers is V 194 between?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

the integer in question lies between 13 and 14.

Step-by-step explanation:

Review the perfect squares in the neighborhood of 194.  The first that came to my mind was 225 (the squre of 15), and then 196 (the square of 14), and then 169, the square of 13.  

Since 169 < x^2 < 196, the integer in question lies between 13 and 14.

Check with a calculator:  √194 ≈ 13.93

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Why is it helpful to write numbers in different ways
Goshia [24]
You should write numbers in as many ways as you possibly can to make new connections in your brain. Knowing how to write numbers in many different ways can help you solve complex problems more easily. Doing this can also reinforce the mathematical principles and logic you have memorised.

Writing one in many different ways:

1=1/1=2/2=3/3=4/4=(-1)/(-1)=(-2)/(-2)

=1.0=1.00=1.000=(1/2)+(1/2)=(1/3)+(1/3)+(1/3)

=(1/4)+(1/4)+(1/4)+(1/4)

Writing a half in many different ways:

1/2=(1/4)+(1/4)=(1/6)+(1/6)+(1/6)

=(1/8)+(1/8)+(1/8)+(1/8)=4*(1/8)

=2/4=3/6=4/8=5/10=0.5=0.50

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6 0
3 years ago
Rewrite the expression 4+ the square root of 16-(4)(5) decided by 2 as a complex number in standard form a+bi
bija089 [108]

Answer: 4 + \sqrt{4i}

Step-by-step explanation:

4+ \sqrt{16-(4)(5)} = 4 + \sqrt{16-20} =4 + \sqrt{-4} = 4 + \sqrt{4i}

if it matters then simply further...

4 + \sqrt{4i} = 4 + 4i^{1/2}

8 0
3 years ago
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I’m so confused?? what’s the question?
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3 0
3 years ago
Help me please i cant seem to get it
givi [52]

The diagnonals of a parallelogram bisect each other ,

so

=》 BD = 3x × 2

=》BD = 6x

and there's given that

=》

BD = \dfrac{3}{5} AC

=》

6x =  \dfrac{3}{5}  \times 40

=》

x =  \dfrac{24}{6}

=》

x = 4

so, if x = 4 , then the given quadrilateral is a parallelogram.

7 0
2 years ago
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