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3 years ago

14

Divide. Write the answer in simplest form.

1 answer:

Irina-Kira [14]3 years ago

4 0

Turn 2 3/4 to an improper fraction (2*4+3=11/4). Then turn your new improper fraction to the reciprocal (switch the two numbers (4/11). Change the division sign to multiplication (3/16*4/11). Then multiply across (12/176). Then simplify by 4 to get. 3/44.

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The distribution of annual profit at a chain of stores was approximately normal with mean \mu = \$66{,}000μ=$66,000mu, equals, d

Pepsi [2]

Answer:

The closest to the maximum profit is $x = \$ 83682$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = \$66,000$

The standard deviation is $\sigma = \$ 21000$

The percentage of profit is 20%

Generally the closest to the maximum annual profit at a store where the executives conducted an audit is mathematically evaluated as follows

$P(X > x ) = 0.20$

=> $P(X > x ) = P(\frac{X -x}{\sigma } > \frac{x -66000}{21000} ) = 0.20$

From the z-table the z-score for 0.20 is

$z-score = 0.842$

So

$\frac{x -66000}{21000} = 0.842$

=> $x = \$ 83682$

4 0

4 years ago

Please help me with the question :)

poizon [28]

SV middle line of trapezoid, so

$\frac{40 + x}{2} = 29 \\ 40 + x = 58 \\ x = 18$

Answer: QR=18

3 0

3 years ago

Please help me!! Also if you can show the steps, I’d appreciate it. Thank you very much

natita [175]

-3x=2x+19
-19 -19
-3x-19=2x
+3x +3x
-19=5x
/5 /5
x=19/5

3 0

3 years ago

ivann1987 [24]

What are the choices ?

7 0

4 years ago

5. Write two expressions for the area of the big rectangle.

4vir4ik [10]

Answer:

Two expressions for the area are;

i) x/3 + 2·y + 6

ii) (1/3) × (x + 6·y + 18)

Step-by-step explanation:

The given dimension of the rectangle are;

The height of the rectangle, h = 1/3

The width of the smallest rectangle, w₁ = x

The width of the med sized rectangle, w₂ = 6·y

The width the large rectangle, w₃ = 18

The area, 'A', of the entire rectangular figure, the big rectangle, can be expressed as follows;

A = A₁ + A₂ + A₃

Where;

A₁ = The area of the smallest rectangle

A₂ = The area of the mid sized rectangle

A₃ = The area of the large rectangle

∴ A = (1/3) × x + (1/3) × 6·y + (1/3) × 18 = x/3 + 2·y + 6

The area of the big rectangle. 'A', can also be found as follows;

A = (1/3) × (x + 6·y + 18)

Therefore, two expressions for the area of the big rectangle are;

x/3 + 2·y + 6 and (1/3) × (x + 6·y + 18).

3 0

3 years ago