What is the area of a circle with a diameter 42 inches

Mathematics

2 answers:

melisa1 [442]2 years ago

6 0

Answer:

1385.44

Step-by-step explanation:

Use the formula for the area of a circle. A = $\pi x^{2}$

Leviafan [203]2 years ago

5 0

Answer: The area of the circle equals 1384.74 in²

Step-by-step explanation: The first and only clue we have here is that the diameter of the circle has been provided, which is 42. That makes the radius equal to 21, since half of a diameter is the radius.

With the area and the radius already known, we shall now express the area as follows

Area of circle = πr²

Area of circle = 3.14 x 21²

Area of circle = 3.14 x 441

Area of circle = 1384.74 in²

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Two types of sandwiches were made for a tea party. 55% of the sandwiches were cheese sandwiches and the rest were chicken sandwi

Helen [10]

"To solve this problem, the formula can be used

I = P / T

Where I is the fraction of the sample

P is the amount of the sample

T is the total amount of sample

Since P = 252 chicken sandwiches and I = 0.55

And solve for T

T = 252 / 0.52

T = 458 sandwiches in total"

hope this helps

7 0

3 years ago

Use the Law of Sines to find the measure of angle J to the nearest degree.

rjkz [21]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)$