We first calculate the z-score corresponding to x = 1075 kWh. Given the mean of 1050 kWh, SD of 218 kWh, and sample size of n = 50, the formula for z is:
z = (x - mean) / (SD/sqrt(n)) = (1075 - 1050) / (218/sqrt(50)) = 0.81
From a z-table, the probability that z > 0.81 is 0.2090. Therefore, the probability that the mean of the 50 households is > 1075 kWh is 0.2090.
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If k = 12, then k + 40 = 12 + 40 = 52.
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Answer:
See below ↓↓
Step-by-step explanation:
<u>Plan 1</u>
<u>Plan 2</u>
<u>Part A</u>
<u>Equating them</u>
⇒ 127x = 363 + 94x
⇒ 33x = 363
⇒ x = <u>11 months [They will be same at this point]</u>
<u>Part B</u>
⇒ Plan 1 : 127(24) = $3048
⇒ Plan 2 : 363 + 94(24) = 2256 + 363 = $2619
⇒ I would recommend Plan 2 as it costs less for the time period of 2 years
Answer:
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