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3 years ago

Plz help me thank you

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

2 cups:16 fluid ounces

96 ounzes: 6 pints

12 pints: 24 cups

4 quarts: 1 gallon

katrin2010 [14]3 years ago

5 0

2 cups=16 oz
96 oz=6 pints
12 pints=24 cups
4 quarts=1 gallon

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PLEASE HELP ASAP WILL MARK BRAINLIEST Solve the quadratic equation 18x^2 -153x -172 =0

Vika [28.1K]

Answer:

The answer is : x = 9.505 and x = -1.005

Step-by-step explanation:

To solve the quadratic equation use the formula :

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}$

Where a is the coefficient of x² , b is the coefficient of x and c is the numerical term

∵ a = 18 , b = -153 and c = -172

∴ $x=\frac{-(-153)+\sqrt{(-153)^{2}-4(18)(-172) } }{2(18)}$

$x = \frac{18+\sqrt{35793} }{36} &x=\frac{18-\sqrt{35793} }{36}$

∴ x = 9.505 and x = -1.005

8 0

3 years ago

A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.3 years, and standard deviation of

Zolol [24]

Answer:

probability of lasting longer = 1.7%

Step-by-step explanation:

We are given:

x' = 14 years

μ = 12.3 years

s = 0.8 years

Thus, let's use the formula for the Z-score value which is;

z = (x' - μ)/s

Thus;

z = (14 - 12.3)/0.8

z = 2.125

From the z-distribution table attached, the p-value is ;

P(x' > 2.125) = 1 - 0.983 = 0.017 = 1.7%

Thus,probability of lasting longer = 1.7%

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2 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus

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3 years ago

How do you solve the equation by factoring or square roots Ex: x^2-4x=0

Lubov Fominskaja [6]

$x^2-4x=0\\
x(x-4)=0\\
x=0 \vee x=4$

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$3x^2=48\\
x^2=16\\
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\hbox{or}\\\\
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3(x^2-16)=0\\
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3 years ago

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Free_Kalibri [48]

Answer:

cheat off somebody who has the answer

Step-by-step explanation:

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2 years ago