Answer:
A. 1/5k - 2/3j and -2/3j +1/5k
Step-by-step explanation:
A. 1/5k - 2/3j and -2/3j +1/5k
B. 1/5k - 2/3j and -1/5k +2/3j
There is a change in the signs of each term
1/5k changed to -1/5k
-2/3j changed to +2/3j
Not equivalent
C. 1/5k - 2/3j and 1/5j - 2/3k
There is a change in the variables
1/5k changed to 1/5j
-2/3j changed to -2/3k
D. 1/5k - 2/3j and 2/3j - 1/5k
The is a change in the signs of each term
1/5k changed to -1/5k
-2/3j changed to +2/3j
The only equivalent expression is
A. 1/5k - 2/3j and -2/3j +1/5k
Pemdas
mutliply first
5*5=25
now we have
25+9+2+2-4+6-2-3
34+2+2-4+6-2-3
36+2-4+6-2-3
38-4+6-2-3
34+6-2-3
40-2-3
38-3
35
Answer:
Step-by-step explanation:
It seems you got the right answer, but didn’t do the problem correctly.
The square root of 2 times the square root of 2 is 2. And then 6 times the square root of two minus the product of 6 and the square root of two equals zero. And then obviously 6 and -6 equals -36. So 2+-36 is -34
1/5 is an expression that represents 1÷5= .2
Since the return decimal equivalent doesn't go on forever and has a finite end, this is a member of the rational number set.
Step-by-step explanation:
let the numbers are:
a, b, and c
the equation would be:
a+b+c = 131
c = 4a
b = a+5
=>
a + a+5 +4a = 131
6a +5 = 131
6a = 131-5
6a = 126
a= 126/6
a = 21
b = a+5 = 21+5
b = 26
c = 4a = 4(21)
c = 84
