The density of a population of living organisms is usually measured in individuals on one square km. In here we have 50 earthworms on an area of 5 square meters, thus we have 10 earthworms on every square meter. In order to get to the result we need to see first how many square meters there are in one square km. One square km has one thousand meters of length and one thousand meters of width so:
1,000 x 1,000 = 1,000,000 km²
Since we established that we have 10 earthworms on every one square meter, we just need to multiply the number of square meters with the amount of earthworms on every square meter:
1,000,000 x 10 = 10,000,000
So we have a density of 10 million earthworms per square km.
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Answer:
the eagle habitat is estuaries, large lakes, reservoirs, rivers, and some seacoasts, but in the winter the eagle congregate near open water in tall trees for spotting prey.
Explanation:
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Answer:
the answer is A. E. coli B
Explanation:
The multiplicity of infection (MOI) refers to the ratio between the numbers of viruses used to infect <em>E. coli</em> cells and the numbers of these <em>E. coli </em>cells. Benzer carried out several experiments in order to define the gene in regard to function. Benzer observed that <em>E. coli </em>strains with point mutations could be classified into two (2) complementary classes regarding coinfection using the restrictive strain as the host. With regard to his experiments, Benzer observed that rII1 and rII2 mutants (rapid lysis mutants) are complementary when they produce progeny after coinfect E. coli K (where neither mutant can lyse the host by itself). The rII group of mutants studied by Benzer does not produce plaques on <em>E. coli</em> K strains that carry phage λ (lysogenic for λ), but they produce plaques on <em>E. coli</em> B strains. This study showed that rIIA and rIIB are different genes and/or cistrons in the rII region.