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kompoz [17]
2 years ago
7

In a class of 40 students, 75% returned their permission slips for the field trip. How many students returned their permission s

lips?
Mathematics
2 answers:
Dmitriy789 [7]2 years ago
4 0

Answer:

30

Step-by-step explanation:

75% can also be written as 3/4. 3/4 can also be written as 30/40, or 30 out of 40, which in this case, means 30 out of 40 kids.

vovikov84 [41]2 years ago
3 0

Answer:

30 Students Returned their Permission Slips

Step-by-step explanation:

In a class of 40 students, 75% returned their permission slips for the field trip. How many students returned their permission slips?

75% of 40 is 30, therefore 30 students returned their permission slips. 75% is equivalent to 3/4,  or 30/40.

Please let me know if you need anymore help

Good luck! :3

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I want to fined out the digree of polynomial 5 x^4 + 3 x^2 + 1
grigory [225]

Answer:

4

Step-by-step explanation:

The degree of a polynomial is the highest degree of a monomial contained within the polynomial. The degree of the monomial is the sum of the exponents on the variables. Example, the degree of -4x^6y is 6+1=7.

Example, the degree of 4x^8 is 8.

So the degree of 5x^4 is 4.

The degree of 3x^2 is 2.

The degree of 1 is 0 since there is no variable in this expression.

So the degree of 5 x^4 + 3 x^2 + 1 is 4.

4 0
2 years ago
Which number is equivalent to 6%? Select all that apply.
a_sh-v [17]

Answer:

0.06 and 6/100

Step-by-step explanation:

6 0
2 years ago
Two dice are thrown. Determine the probability of obtaining a score of at least 4.
VashaNatasha [74]

11/36 would be the probability of getting 4 , when two dice are thrown simultaneously.

As there are 6 faces of die,
So Probability of Not getting four in one dice = 5/6

As both events are mutually exclusive, the probability of not getting four in two dice = (5/6) * (5/6) = 25/36

So probability of getting at least one four is = 1-(25/36) = 11/36

So probability = 11/36

Learn more about probability refer:

brainly.com/question/24756209

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6 0
2 years ago
Inez earns $160 per month by babysitting she save 25% of our monthly salary average salary increases by 10% how much will she no
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She will now save $56 every month.  Please Mark Brainliest!!!
8 0
3 years ago
The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5
Alexeev081 [22]

Answer:

The null and alternative hypothesis are:

H_0: \mu=5.5\\\\H_a:\mu< 5.5

At a significance level of 0.05, there is enough evidence to support the claim that the population percentage of SiO2 is signficantly different from 5.5%.  

P-value = 0.000004.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population percentage of SiO2 is signficantly different from 5.5%.

Then, the null and alternative hypothesis are:

H_0: \mu=5.5\\\\H_a:\mu< 5.5

The significance level is 0.05.

The sample has a size n=16.

The sample mean is M=5.21.

The standard deviation of the population is known and has a value of σ=0.26.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{0.26}{\sqrt{16}}=0.065

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{5.21-5.5}{0.065}=\dfrac{-0.29}{0.065}=-4.462

This test is a left-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z

As the P-value (0.000004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that the population percentage of SiO2 is signficantly different from 5.5%.

3 0
3 years ago
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