So you can buy $4 pack of $800 each, or buy $7 packs of $500 each.
Answer:
Part 1
Multiply both sides by 2π
2πf = √(g/L)
Square both sides
4π²f²= g/L
Invert both sides
1/(4π²f²) = L/g
Multiply both side by g
g/(4π²f²) = L
We usually write an equation with the subject (L) n the left
L = g/(4π²f²)
________________________
Part 2
Using the above equation with the given values:
L = g/(4π²f²)
. .= 9.8 / (4π² x 1.6²)
. .= 0.097m (= 9.7cm)
________________________
By the way, where it says
“f=1.6 then there are 2 beats a second, or 192 beats per minute (bpm).”
this should say
“f=1.6 then there are 3.2 beats a second, or 192 beats per minute (bpm)”
Step-by-step explanation:
Answer:

Step-by-step explanation:

Answer:
1 : 200000
Step-by-step explanation:
4 cm ⇒ 8 km
4 cm ⇒ 8 × 1000m
4cm ⇒ 8000m
4 cm ⇒ 8000 × 100 cm
4 cm ⇒ 800000cm
4 : 800000

1 : 200000
Therefore,
1 : n
1 : 200000
Hope this helps you.
Let me know if you have any other questions :-)
Answer:
The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean is:

The margin of error for this interval is:

The information provided is:
<em>σ</em> = $569
MOE = $140
Confidence level = 95%
<em>α</em> = 5%
Compute the critical value of <em>z</em> for <em>α</em> = 5% as follows:

*Use a <em>z</em>-table.
Compute the sample size required as follows:
![n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 569}{140}]^{2}\\\\=63.457156\\\\\approx 64](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%20569%7D%7B140%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D63.457156%5C%5C%5C%5C%5Capprox%2064)
Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.