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Sonja [21]
4 years ago
12

A game involves rolling a fair six-sided die. If the number obtained on the die is a multiple of three, the player wins an amoun

t equal to the number on the die times $20. If the number is not a multiple of three, the player gets nothing.
Mathematics
1 answer:
mrs_skeptik [129]4 years ago
7 0

Answer:

Winning probability is \frac{1}{3}

Step-by-step explanation:

Favourable outcomes to win are 3 and 6.

Total outcomes are six in fair dice.

So , probability of winning some money =\frac{2}{6}=\frac{1}{3}

To win $20*3 or $20*6 favourable outcome is 1 (3 and 6 respectively)

Thus probability =\frac{1}{6}

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  • The solution for the compound inequality is: -0.5 < x \leq 2
  • The graph is given at the end of the question.

--------------------------------

The compound inequality is given by:

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Thus, we need:

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That is, values of x that respect both these conditions.

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For the first inequality:

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  • The graph on the number line is given next.

A similar problem is given at brainly.com/question/24009950

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