Ask question

Ask question

All categories

3 years ago

8

In New York State, 48% of all teenagers own a skateboard and 39% of all teenagers own a skateboard and roller blades. and 5% of

teens own neither. What is the probability that a teenager owns roller blades?

1 answer:

Ulleksa [173]3 years ago

8 0

Answer:

18.72%

Step-by-step explanation:

39% of 48 is 18.72

Hope this helps!

You might be interested in

When would you use a table to display data?<br> When would you would use a graph to display data?

dexar [7]

A table would help to organize more information than a graph would. A graph would help more with numbers.

6 0

3 years ago

If A and B represent integers, M+P = P+M is an example of which property?

Serggg [28]

Answer:

commutative propriety of addition

Step-by-step explanation:

M+P =P+M is an example of the commutative propriety of addition

when numbers or parentheses connected by addition or multiplication switch places (commute) we have commutative propriety of addition or multiplication

8 0

2 years ago

Read 2 more answers

A triangle has angles that measure 46 and 84<br><br> what is the third angle?

pentagon [3]

The measure of the third angle is 50 because a triangle has a sum of 180 degrees by angle.

so... 46+84=130 and to get to 180, the last angle has to be worth 50.

5 0

3 years ago

Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago

What is the completely factored form of this expression?

Eddi Din [679]

Answer:

B.

(3x + 4)(x − 7)

Step-by-step explanation:

If you multiply.

3x2-21x+4x-28

3X2-17x-28

8 0

3 years ago