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Anestetic [448]
3 years ago
12

I will give branliest!

Mathematics
2 answers:
Serhud [2]3 years ago
8 0

Answer:1: 1 + 12- += -11

2:2 +13-= -11

Step-by-step explanation: i can't see the other one i tryed my best.

Anon25 [30]3 years ago
3 0
-3+-8=-11
-8+-3=-11

(-11)-(-8)=-3
(-11)-(-3)=-8
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Determine whether the improper integral converges or diverges, and find the value of each that converges.
Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

u=x             dv=e^(2x)\cdot{dx}

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4 years ago
Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square
ValentinkaMS [17]

Answer:

Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = 11\frac23\ yd^2

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator,  Add that to the numerator,Then write the result on top of the denominator.

11\frac23\ yd^2 can be Rewritten as \frac{35}{3}\ yd^2

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Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = \frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2

Amount of fabric left with Richard = \frac56 \ yd^2

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac56

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project  = \frac{35-10}{12}= \frac{25}{12}\ yds^2

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Hence Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

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6 0
3 years ago
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