Please help, multiple choice
1 answer:
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Answer:
The p-value for this test is 0.22065.
Step-by-step explanation:
We are given that a national study report indicated that 20.9% of Americans were identified as having medical bill financial issues.
A news organization randomly sampled 400 Americans from 10 cities and found that 90 reported having such difficulty.
<u><em>Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.</em></u>
SO, Null Hypothesis, : p
20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}
Alternate Hypothesis, : p > 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}
The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;
T.S. = ~ N(0,1)
where, = sample proportion of 400 Americans from 10 cities who were found having such difficulty =
= 0.225 or 22.5%
n = sample of Americans = 400
So, <u><em>test statistics</em></u> =
= 0.77
<u></u>
<u>Now, P-value of the test statistics is given by the following formula;</u>
P-value = P(Z > 0.77) = 1 - P(Z 0.77)
= 1 - 0.77935 = 0.22065
Answer to A:
50%
Explanation for A:
We're looking for how many numbers are odd, so theres 1, 3, 5 ,7, four numbers.
We have a total of 8 numbers.
To make any number a percent we move the point over to the right by two, which makes our final answer 50%
Answer to B:
37.5%
Explanation for B:
If the number is less than four, that means we need to find if it will roll the first three numbers. We, once again, have eight total possibilities
0.375 can be turned into our final answer, 37.5%