Answer:
x = 18
y = 15
Step-by-step explanation:
Remark
Step One
The main step is to realize that if the lower left hand angle is 90 degrees, then the upper left hand angle is also 90. That is because the interior angles of parallel lines are supplementary. If one of the angle is 90 degrees, so is the other.
<em><u>Conclusion from the Remark</u></em>
5x = 90
x = 90/5
x = 18 degrees
Step Two
Find y
y is just a bit harder to find . The safest way is to add all four interior angles together. For any trap*zoid (you cannot spell this word properly. The editor has a fit), the interior angles add up to 360 degrees.
So just add the 4 angles together and equate to 360
5(y + 11) + 4y - 10 + 90 + 90 = 360 Combine like terms
5(y + 11) + 4y - 10 + 180 = 360 Combine again
5(y + 11) + 4y + 170 = 360 Subtract 170 from both sides
5(y + 11) + 4y = 360 - 170 Combine like terms
5(y + 11) + 4y = 190 Remove the brackets
5y + 55 + y4 = 190 Combine like terms
9y + 55 = 190 Subtract 55 from both sides.
9y = 190 - 55
9y = 135 Divide by 9
y = 135 / 9
y = 15
Answer:
i so sory i dont know :(
Step-by-step explanation:
One foot = 12 inches.
32 feet = x inches
x/12=32/1
so
x=12*32/1 inches per second^2
Answer:
(a)
(b)5,832 Mosquitoes
(c)5 days
Step-by-step explanation:
(a)Given an original amount
at t=0. The population of the colony with a growth rate
, where k is a constant is given as:

(b)If
and the population after 1 day, N(1)=1800
Then, from our model:
N(1)=1800

Therefore, our model is:

In 3 days time

The population of mosquitoes in 3 days time will be approximately 5832.
(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.
From our model

In approximately 5 days, the population of mosquitoes will be 20,000.