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nika2105 [10]
3 years ago
10

There are 175 lights on a tree. There are five more

Mathematics
1 answer:
zimovet [89]3 years ago
6 0

For red we could use the variable r and G for green, and c for clear.

Red is G+5

G is R-5

C is Rx3

This is like a guessing Game, you guess and check.

R=36

G=31

C=108

36+31+108=175

Mark Me Brainliest pls  I lost 4 brain cells doing this TwT

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For more information I use photomath and it give free answers with explanation.

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Solve the system of equations y=5x y=x^2+4<br> answer:(1,5) and (4, 20)
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Which expression is equivalent to (7x + 6) - (4x + 2)?
nlexa [21]

Answer:

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7 0
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Read 2 more answers
9 friends are lining up. Joe, Susan, John, and Meredith must be beside each other. How many ways can they line up?
ZanzabumX [31]
<h3>Answer:  17,280</h3>

This is one single number slightly over 17 thousand.

You may need to erase the comma when typing the answer in.

=========================================================

Explanation:

Let's say that another person steps in for Joe, Susan, John, and Meredith. I'll refer to this person as the teacher (perhaps these 9 friends are students on a field trip).

The 9 friends drops to 9-4 = 5 people when those four named people leave the group temporarily. Then it bumps up to 5+1 = 6 people when the teacher steps in. Wherever the teacher is located, the four friends that left will replace the teacher. This guarantees that those four friends stick together.

There are 6! = 6*5*4*3*2*1 = 720 ways to arrange those 6 people. The exclamation mark is a factorial symbol.

Within any of those 720 permutations, we have 4! = 4*3*2*1 = 24 ways to arrange those group of named people when they come back to replace the teacher.

So overall the answer is 4!*6! = 24*720 = 17,280

You may need to erase the comma when typing the answer in.

-------------

Side note: There are 9! = 362,880 ways to arrange all nine friends regardless if those four mentioned people stick together or not. We see that they stick together roughly (17,280)/(362,880) = 0.0476 = 4.76% of the time.

6 0
3 years ago
Joe has collections of 35 DVD movies. He received eight of them as gifts. Jobot the rest of his movies over three years. If he b
Yuliya22 [10]
Hello!

Let's subtract the eight DVDs Joe received as gifts, because he didn't buy them on his own.

35 - 8 = 27

Now, divide the remaining CDs by the 3 years he collected his DVDs in.

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A N S W E R:

Joe bought 9 DVDs last year.

Good day!
8 0
3 years ago
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