Answer:
O is the center of the circle with radius IE(=ID=EF)
Step-by-step explanation:
Join all 3 points D, E, F, forming the triangle DEF.
Let the midpoint of EF be M and the midpoint of ED be N. (first picture)
Join point I to E, D and F.
Since IN is both an altitude and median to triangle EID, then triangle EID is an isosceles triangle, and IE=ID
similarly, we see that IE=IF.
conclusion: IE=ID=EF.
(D) hope this helps kxjdndldjdkwpwnx
Answer:
The answer is 0.54 have a great day
Answer:
BC = 17.2.
Step-by-step explanation:
Since CAB = 90º, this is a right triangle.
The triangle format is given below:
C
A B
We have that AB = 8.6, and angle B measures 60º.
Length of BC:
BC is the hypotenyse.
Side AB is adjacent to angle B = 60º.
In a right triangle, angle 
, it's adjacent side with length s and the hypotenuse h are related by the cosine of the angle, that is:
In this question, we have an angle of 60º, with has cosine 0.5. We also have that side AB = s = 8.6, and the hypotenuse h is side BC. So
BC = 17.2.
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
