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serious [3.7K]
3 years ago
8

On a number line, what number is between 1/4 and 1/5?

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

ez 9/40

Step-by-step explanation:

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Janelle has $75. She buys jeans that are on sale for half price and then uses an in-store coupon for $10 off. After paying $1.80
kramer
75.00-37.20=37.80-1.80=36.00
so she spent 36.00 with sales tax . then 36.00*2=72.00+10.00=82.00
the jeans original price was 82.00 
 Check:
6 0
3 years ago
48w + 42x. Write you're answere as a product with a whole number greater than 1???
Natali [406]

Answer:

6(8w + 7x)

Step-by-step explanation:

Hello!

The greatest common factor between 48 and 42 is 6. We can factor out 6 from each term.

<h3>Factor</h3>
  • 48w + 42x
  • 6(8w) + 6(7x)
  • 6(8w + 7x)

The expression is 6(8w + 7x).

4 0
1 year ago
Read 2 more answers
10. Volume =<br><br> pls help me i wanna go home ;(
frosja888 [35]

Answer:

1248 cm^2

Step-by-step explanation:

Volume = Length · Width · Height

Volume = 24 · 6 · 5

Volume = 720 cm^2

Volume = Length · Width · Height

Volume = 8 · 6 · 11

Volume = 528 cm^2

528 + 720 = 1248

6 0
3 years ago
Read 2 more answers
Express each of these statements using quantifiers. Then form the negation of the statement so that no negation is to the left o
solniwko [45]

Answer and Step-by-step explanation:

Not p = ¬p

P or q = p ∨ q  

P and q = p ∧ q

If p then q = p → q

P if and only if q = p ↔ q

Existential quantification:  There exist an element x in the domain such that p(x).

Universal quantification: p(x) for all values of x in the domain.

(a)  No one has lost more than one thousand dollars playing the lottery.

Let A(x) means ‘x has lost more than one dollars playing the lottery’

It can also write as “there does not exists a person that lost more than one thousand dollars playing”

                     ¬Ǝ x A (x)

Negation of this statement:  

By using double negation law:

                               ¬ [¬Ǝ x A (x)]  ≡ Ǝ x A(x)

(b) There is a student in this class who has chatted with exactly one other student.

Let B(x,y) means “ x has chatted with y” and domain is all students of this class.

We can write the given sentence as:

“There is a student in the class who has chatted with one student and this student is not himself and for all people the student chatted with, this student has to be himself or the one student he chatted with”

Ǝ x Ǝ y[B ( x, y) ∧ x ≠ y ∧ ∀ z (B(x,y) → ( z = x v z = y))]

The negation:

               ¬ Ǝ x Ǝ y[B ( x, y) ∧ x ≠ y ∧ ∀ z (B(x ,y) → ( z = x v z = y))]

By using De Morgan’s law for quantifiers:

≡∀x ¬ Ǝ y [B ( x, y) ∧ x ≠ y ∧ ∀ z (B(x ,y) → ( z = x v z = y))]

≡∀x ∀ y [B ( x, y) ∧ x ≠ y ∧ ∀ z (B(x ,y) → ( z = x v z = y))]

De Morgan’s law:

≡∀x ∀ y [¬  B ( x, y) v  ¬ ( x ≠ y) v ∀ z (B(x ,y) → ( z = x v z = y))]

By using De Morgan’s law for quantifiers:

≡∀x ∀ y [¬  B ( x, y) v  x=  y  v Ǝ z¬ (B(x ,z) → ( z = x v z = y))]

(c)  No student in this class has sent e-mail to exactly two other students in this class

Let c(x, y) means “ x has sent email to y” and the domain is all student of class.

Using double negation law:

Ǝ x Ǝ y Ǝ z [c(x, y) ∧c(x ,z) ∧ x≠ y ∧ x ≠z ∧ y ≠ z ∀ w (c(x,w) → ( w = x v w = y v w = z)]

There is a student in class that has sent email to exaxtly two other students in class.

(d)  One student has solved every exercise in this book

Let D(x , y) mean student x has solved exercise y in this book.

The negation:  

Ǝx∀yD(x,y)

Use De Morgan’s law for qualifiers:

    ≡∀ x Ǝ y ¬D(x, y)  

(e). No student has solved at least one exercise in every section of this book.

Let E(x, y,z) be student x has solved exercise y in section z of this book.

We can write “there does not exist a student that solved at least one exercise in all sections of this book”

¬Ǝ x Ǝ y ∀ Z E(x, y, z)  

Negation:

                      ≡¬ [¬ Ǝ x Ǝ y ∀ Z E(x, y, z)  ]

Use double negation law:

                                     ≡ Ǝ x Ǝ y ∀ Z E(x, y, z)  

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7 0
3 years ago
What is 17 to 100 as a percent?
Delvig [45]
17% u divide 17 by 100 and then multiply by 100
5 0
3 years ago
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