Which statement describes the end behavior of the exponential function f(x)=2^x-3

Write an inequality to show how much more needs to be saved to reach $100?

pentagon [3]

It’s d or a but it’s probably d don’t take my word for it boy

8 0

2 years ago

Read 2 more answers

Find the missing length indicated. 18 ? 4 8 A) 21 C) 9 B) 3 D) 25

Reika [66]

I think the answer is 9

8 0

2 years ago

Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:

professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is $\{1,2,3,4\}$ .

a) We need to find a relation R reflexive and transitive that contain the relation $R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}$

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

1R4 and 4R1, then 1 must be related with itself.
4R1 and 1R4, then 4 must be related with itself.
4R1 and 1R2, then 4 must be related with 2.

Therefore $\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\}$ is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

since 1R2, then 2 must be related with 1.
since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

1R2 and 2R1, then 1 must be related with itself.
4R1 and 1R4, then 4 must be related with itself.
2R1 and 1R4, then 2 must be related with 4.
4R1 and 1R2, then 4 must be related with 2.
2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

$\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}$

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

1 must be related with 1,

2 must be related with 2,

3 must be related with 3,

4 must be related with 4

For be symmetric

since 1R2, 2 must be related with 1,
since 1R4, 4 must be related with 1.

For be transitive

Since 4R1 and 1R2, 4 must be related with 2,
since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

$\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}$

5 0

2 years ago

18 Andy flies from the UK to Japan.

kotykmax [81]

Answer:

Leila pays more than Andy to fly from the UK to Australia.

Step-by-step explanation:

Given:

Andy flies from the UK to Japan.

His plane ticket costs £554.

Andy then flies from Japan to Australia.

His plane ticket costs 70 140 Japanese Yen.

The exchange rate is £1 = 140 Japanese Yen.

Leila flies from the UK to Australia.

Her plane ticket costs 1860 Australian dollars.

The exchange rate is 1 Australian dollar = £0.62.

Now, to find Andy or Leila who pays more to fly from the UK to Australia.

Andy flies from the UK to Japan.

His plane ticket costs = £554.

Andy then flies from Japan to Australia.

His plane ticket costs 70 140 Japanese Yen.

The exchange rate is £1 = 140 Japanese Yen.

So, by using conversion factor we convert Japanese Yen to £.

140 = £1

70140 = $70140\div 140=\£501.$

His plane ticket costs = £501.

Now, adding both the cost of tickets:

$501+554=\£1055.$

Andy total pays fly from the UK to Australia is £1055.

Now, to get the cost of plane ticket of Leila from the UK to Australia.

Her plane ticket costs 1860 Australian dollars.

The exchange rate is 1 Australian dollar = £0.62.

So, by using conversion factor:

1 Australian dollar = £0.62

1860 Australian dollar = $1860\times 0.62=\£1153.2$

Her plane ticket costs is £1153.2.

As, we see that cost of plane ticket of Andy is £1055 and cost of plane ticket of Leila is £1153.2.

Thus, Leila pays more.

Therefore, Leila pays more than Andy to fly from the UK to Australia.

4 0

3 years ago

The point p (3,4) is the midpoint of the join of A (7,8) and B find tge coordinates of B

Shalnov [3]

Answer:

B(-1, 0)

Step-by-step explanation:

coordinates of midpoint p(x,y) are calculated as

$x= \frac{x_1+x_2}{2}$ ---------- (1)

$y= \frac{y_1+ y_2}{2}$ -----------(2)

Here $(x_1, y_1) = (7, 8)$ and $(x_2, y_2) \ is \ unkwon$

Using equation (1)

$3=\frac{7+x_2}{2} \\x_2=-1$

Using equation (2)

$4=\frac{8+y_2}{2} \\y_2=0$

3 0

3 years ago