The middle person in a row is the 18th, how many persons are in the row?

Take a factor out of the square root:

Allisa [31]

Answer:

Question A)

$=\sqrt{6}x$

Question B)

$=3a\sqrt{a}$

Question C)

$=5\sqrt{2}b^2$

Step-by-step explanation:

A)

We are given:

$\sqrt{6x^2}\, \text{ where } x\geq 0$

We can rewrite the expression:

$=\sqrt{6}\cdot \sqrt{x^2}$

The square root and square will cancel each other out. Thus:

$=\sqrt{6}x$

B)

We are given:

$\sqrt{9a^3}$

Rewrite:

$=\sqrt{9}\cdot \sqrt{a^3}$

Note that the square root of 9 is simply 3. We can also factor the second part:

$=3\cdot \sqrt{a^2\cdot a}$

Rewriting:

$=3\cdot\sqrt{a^2}\cdot\sqrt{a}$

Simplify:

$=3a\sqrt{a}$

C)

We are given:

$\sqrt{50b^4}$

Rewrite. Note that 50 = 25(2):

$=\sqrt{25}\cdot \sqrt{2}\cdot \sqrt{b^4}$

Simplify. We can rewrite the factor as:

$=5\cdot \sqrt{2}\cdot \sqrt{(b^2)^2}$

The square and square root will cancel out. Thus:

$=5\sqrt{2}b^2$

8 0

3 years ago

Whoshand was bigger 0.17 m or 0.165 m

S_A_V [24]

O.17 because it can also be 0.170 witch is still bigger then 0.165

5 0

3 years ago

classify each scale factor as a contraction or an expansion Dragon drop the choices into the box to complete the table

TEA [102]

Anything that is multiplied by a number over 1 will get bigger. any other number such as negatives or fractions/decimals will get smaller. 1.25 and 3 are expansions and -2,3/4, and 1/5 are contractions

8 0

3 years ago

Read 2 more answers

Shakila bought a purse for $120. the tax rate is 9%. what is the total amount Shakila paid?

olga nikolaevna [1]

Shakila paid $130.80 in total.
Explanation: 120*1.09=130.80

7 0

3 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago