Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
57° F is converted to: 13.889° Celcius if you don't factor to the nearest tenth. Doing so would make it 13.9° Celcius.
I hope this is the answer you were looking for and that it helps!! :)
Answer:
- 3a³ + 5a² - 3a + 7
Step-by-step explanation:
Given
(a³ - 2a + 5) - (4a³ - 5a² + a - 2)
Distribute both parenthesis noting the second is distributed by - 1
= a³ - 2a + 5 - 4a³ + 5a² - a + 2 ← collect like terms
= (a³ - 4a³ ) + 5a² + (- 2a - a) + (5 + 2)
= - 3a³ + 5a² - 3a + 7
Answer:
Mass = no. of molecules / 6.023 * 10^ 23 * Molar mass
Step-by-step explanation:
Molar mass of CO2 = 44g/mol
1.5
⋅
10
25
6.023
⋅
10
23
= 51.5 moles of CO2
51.5
⋅
44g/mol
=
2266 grams
Hope this helped
Answer:
x > 3/14
Step-by-step explanation: