Answer:
7
Step-by-step explanation:
Answer:
$4,316
Step-by-step explanation:
Semester one: $166 per credit times 13 hours = $2,158
Semester two: $166 per credit times 13 hours = $2,158
Cost for semester one plus semester two = $4,316
The complete question is
Find the volume of each sphere for the given radius. <span>Round to the nearest tenth
we know that
[volume of a sphere]=(4/3)*pi*r</span>³
case 1) r=40 mm
[volume of a sphere]=(4/3)*pi*40³------> 267946.66 mm³-----> 267946.7 mm³
case 2) r=22 in
[volume of a sphere]=(4/3)*pi*22³------> 44579.63 in³----> 44579.6 in³
case 3) r=7 cm
[volume of a sphere]=(4/3)*pi*7³------> 1436.03 cm³----> 1436 cm³
case 4) r=34 mm
[volume of a sphere]=(4/3)*pi*34³------> 164552.74 mm³----> 164552.7 mm³
case 5) r=48 mm
[volume of a sphere]=(4/3)*pi*48³------> 463011.83 mm³----> 463011.8 mm³
case 6) r=9 in
[volume of a sphere]=(4/3)*pi*9³------> 3052.08 in³----> 3052 in³
case 7) r=6.7 ft
[volume of a sphere]=(4/3)*pi*6.7³------> 1259.19 ft³-----> 1259.2 ft³
case 8) r=12 mm
[volume of a sphere]=(4/3)*pi*12³------>7234.56 mm³-----> 7234.6 mm³
Perimeter is the lengths of the edges added up. And if the shape is a rectangle, there are 4 edges so we divide by 4. 44/4=11. each of the four sides are 11 feet long.
width=11
length=11
area=width*length=121
Answer:
The probe's final position is -143m
Step-by-step explanation:
Note that the words 'lowered' and 'below' mean subtract; while the word 'raised' means add. Thus, interpreting the statement to mathematical expression is done below.
Therefore, the probe's final position is -143m. Hence, the sensor is 143m below the sea level.
