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3 years ago

PLEASE HELP I RLY NEED THIS! I BEG YALL PLEASE HELP ME !

Mathematics

1 answer:

GalinKa [24]3 years ago

8 0

Answer:

The answer would be 30/13.

Step-by-step explanation:

Votes for the skating rink= 30

Votes for the bowling alley= 13

Ratio of the # of votes for skating <u>TO</u> the # of votes for the bowling alley= 30/13.

Hope this helps! :)

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Thanks to all those who support my question!

Mazyrski [523]

Answer:

no, because intergers are negative. they will never be able to be greater

Step-by-step explanation:

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3 years ago

Read 2 more answers

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

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2 years ago

What is 17 divided by 18

Liono4ka [1.6K]

Answer:

1.05

Step-by-step explanation:

6 0

3 years ago

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I need help on this problem! <br><br> g(h+2/3)=1 for h

Tju [1.3M]

Answer:

$g(h + \frac{2}{3} ) = 1 \\ \\ gh + \frac{2}{3} g = 1 \\ \\ gh = 1 - \frac{2}{3} g \\ \\ h = (1 - \frac{2}{3} g ) \div g \\ \\ h = (1 - \frac{2}{3} g ) \times \frac{1}{g} \\ \\ h = \frac{1}{g} - \frac{2}{3}$

I hope I helped you^_^

7 0

3 years ago

NO LINKS OR ASSESSMENT!!!<br>Part 6: Write a rule to describe each transformation.<br>

Scrat [10]

Answer:

(x, y) → (x, y - 3)

Step-by-step explanation:

We observe a vertical shift.

The shift is negative by 3 units.

<u>The rule for this translation is:</u>

(x, y) → (x, y - 3)

6 0

2 years ago