1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ANTONII [103]
3 years ago
6

I am having trouble with mean absolute deviation and whisker box plots. I try looking at examples, but it keeps stressing me out

. I just can't understand it X(
Mathematics
1 answer:
Arada [10]3 years ago
8 0

Answer:

Mean absolute deviation is a statistical measure of dispersion. Whisker box-plot is a graphical method of quartile based divided data

Step-by-step explanation:

Mean Absolute Deviation is a statistical measure of dispersion or variability  in data. It denotes average level of deviation of observations from the central mean.

It is calculated using following formula : ( Σ | X - X' | ) ÷ N ; where X = individual observations, X' = mean, N = no. of observations

Whisker Box-plot is a graphical method of representing group of numerical data through their quartiles. This also consists line extensions from boxes, showing scatter beyond lower & upper quartile.

You might be interested in
Help, I'm doing rhis problem and need help checking if I'm right.
umka2103 [35]
To me it looks like your right
7 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude
DaniilM [7]

Answer:

The answer is "\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\"

Step-by-step explanation:

Given values:

\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39

Using formula:

\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\

Put the values in the above formula:

\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\

4 0
3 years ago
Question 6
oee [108]

Answer:

The answer is 200km

Step-by-step explanation:

250\5=50,50×4=200

7 0
3 years ago
Please help need it asap
densk [106]
The extraneous root is
x = 2
7 0
3 years ago
Other questions:
  • The city tim lives in has 106,534 people. what is the value of the 6 in 106,534?
    6·2 answers
  • I need help please. I don't get how to do systems of linear equations!!!!!!!
    11·1 answer
  • Is this answer correct ?
    14·2 answers
  • Given that cos 160= -q, express each of the following in terms of q:
    8·2 answers
  • How is the rangeof a set of data different from a IQR
    9·2 answers
  • 24 PTS. MARK AS BRAINY!! Help me... I'm desperate... :(
    8·2 answers
  • Daniel, Clarence, and Matthew split a $20.20 dinner bill so that Daniel pays half of what
    7·1 answer
  • All you need is in the photo please
    15·1 answer
  • A total of 250 people were surveyed about whether or not each person carries a cell phone.The results are shown below in relativ
    11·1 answer
  • 1/3 ÷ 3/8<br><br>O 8/9 <br>O 1 1/8 <br>O 1/8​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!