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ANTONII [103]
2 years ago
6

I am having trouble with mean absolute deviation and whisker box plots. I try looking at examples, but it keeps stressing me out

. I just can't understand it X(
Mathematics
1 answer:
Arada [10]2 years ago
8 0

Answer:

Mean absolute deviation is a statistical measure of dispersion. Whisker box-plot is a graphical method of quartile based divided data

Step-by-step explanation:

Mean Absolute Deviation is a statistical measure of dispersion or variability  in data. It denotes average level of deviation of observations from the central mean.

It is calculated using following formula : ( Σ | X - X' | ) ÷ N ; where X = individual observations, X' = mean, N = no. of observations

Whisker Box-plot is a graphical method of representing group of numerical data through their quartiles. This also consists line extensions from boxes, showing scatter beyond lower & upper quartile.

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A ray that divides an angle into two angles that both have the same measure.
VARVARA [1.3K]

Answer:

Angle bisector

Step-by-step explanation:

Bisector means that the two angles have the same measure and it is an angle bisector because it is separating angles.

3 0
3 years ago
5
a_sh-v [17]

Answer:

I could be wrong, but I believe that the answer is D, none. This is because there is only proof of one congruent side and angle.

Step-by-step explanation:

4 0
2 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
Virty [35]

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Y=x-3 and y=-3x+25 in substitution form
Vlad1618 [11]
(x-3)=-3x+25

Because we know that y=x-3 so we put that in place of y in the equation
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3 years ago
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