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kumpel [21]
3 years ago
7

Rodney drops a ball from the bridge at an initial height of 220 feet. How many seconds after the ball is released will it hit th

e ground? Write an equation to model this situation. Solve for time in seconds. Show work
Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

t = √(2d/g); 3.70 s  

Step-by-step explanation:

The formula for the distance (d) travelled by a falling object in time (t) is  

d = ½gt²

Multiply each side by 2                    2d = gt²

Divide each side by g                 (2d/g) = t²

Take the square root of each side     t = √(2d/g)

Data:

d = 220 ft

g = 32.17 ft·s⁻²

Calculation:

t = √ [(2 × 220)/32.17] = √13.68 = 3.70 s

The ball will hit the ground 3.70 s after it is released.

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