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TiliK225 [7]
2 years ago
6

Brent paid for six avocados with a $20 bill he received $10.40 in change construct and solve the equation can be used to find th

e price of each avocado
Mathematics
2 answers:
sleet_krkn [62]2 years ago
8 0
Step 1:
Work out how much is was for 6 avocados
20 - 10.40 = 9.6

Step 2:
Find out how much it is for 1 avocado
9.6 / 6 = $1.6

Step 3:
Construct an equation, where y is how many avocados
1.6y = total price

umka2103 [35]2 years ago
3 0
Answer is : D


Let's start with finding out how much he had to pay. 20-10.40 will give us that answer. That will equal the cost of 6 avocados, giving us an equation of
20 - 10.40 = 6p
Now we'll see which equations match this. Bingo! Answer number D is the same equation with 10.40 added on both sides.
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Answer:

h = 10sin(π15t)+35

Step-by-step explanation:

The height of the blade as a function f time can be written in the following way:

h = Asin(xt) + B, where:

B represets the initial height of the blade above the ground.

A represents the amplitud of length of the blade.

x represents the period.

The initial height is 35 ft, therefore, B = 35ft.

The amplotud of lenth of the blade is 10ft, therefore A = 10.

The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π

Finally the equation that can be used to model h is:

h = 10sin(π15t)+35

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(12,24)
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Answer:

Your answer is :

B. 6a^2 + 3ab

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Step-by-step explanation:

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To compare two programs for training industrial workers to perform a skilled job, 20 workers are included in an experiment. Of t
nikklg [1K]

Answer:

t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805  

p_v =P(t_{(18)}

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

Step-by-step explanation:

Data given and notation

We can calculate the sample mean and deviation with these formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_{1}=19.1 represent the mean for the sample mean for 1

\bar X_{2}=23.3 represent the mean for the sample mean for 2

s_{1}=4.818 represent the sample standard deviation for the sample 1

s_{2}=5.559 represent the sample standard deviation for the sample 2

n_{1}=10 sample size selected 1

n_{2}=10 sample size selected 2

\alpha represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:

Null hypothesis:\mu_{1} \geq \mu_{2}

Alternative hypothesis:\mu_{1} < \mu_{2}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=10+10-2=18

Since is a one sided test the p value would be:

p_v =P(t_{(18)}

Conclusion

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

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Step-by-step explanation:

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