Solution :
Given :
The mean height of an American adult = 5 feet 10 inches
Therefore converting feet into inches,
We know, 1 feet = 12 inches
So, 5 feet = 5 x 12 = 60 inches
The mean height in inches = 60+10
= 70 inches
The standard deviation = 3 inches
x = 5 feet 7 inches
= 5 x 12 + 7
= 67 inches
∴ z score = 



Therefore, the man's height is 1 standard deviation below mean
Any score above greater than 3 or less than -3 is considered to be an outliner.
Here its only -1 and it is less than -3.
Therefore, the height of the man 5'7'' is not considered abnormally short.
check the transformation template below, hmmm so to get the graph of "y" move to the right by 1 unit, we can simply make C = -1.

now, the x-intercept is simply where the graph touches the x-axis, and when that happens y = 0, so
![\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^{log_a x}=x\leftarrow \textit{let's use this rule} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{y}{0}~~ = ~~\log_2(x-1)\implies 2^0=2^{\log_2(x-1)}\implies 2^0=x-1 \\\\\\ 1=x-1\implies 2=x~\hspace{10em}\stackrel{x-intercept}{(2~~,~~0)}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%20%5C%5C%5C%5C%20log_a%20a%5Ex%20%3D%20x%5Cqquad%20%5Cqquad%20a%5E%7Blog_a%20x%7D%3Dx%5Cleftarrow%20%5Ctextit%7Blet%27s%20use%20this%20rule%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7By%7D%7B0%7D~~%20%3D%20~~%5Clog_2%28x-1%29%5Cimplies%202%5E0%3D2%5E%7B%5Clog_2%28x-1%29%7D%5Cimplies%202%5E0%3Dx-1%20%5C%5C%5C%5C%5C%5C%201%3Dx-1%5Cimplies%202%3Dx~%5Chspace%7B10em%7D%5Cstackrel%7Bx-intercept%7D%7B%282~~%2C~~0%29%7D)
X - y > 2 at (5, 4)
5 - 4 > 2
1 > 2
(5, 4) is not a solution to this inequality
Answer:
1.) Reflect across x-axis
2.) Reflect across y-axis
3.) Move to the right by one unit
Step-by-step explanation: