The Factor Theorem says (x - a) is a factor of function p(x) if p(a)=0
so check for p(-2)
= -2^4 +3(-2)^3 + 4(-2)^2 - 8
= 16 - 24 +16 -8
= 0
so (x + 2) is a factor
Answer:
21, 23, 25
Step-by-step explanation:
Ok, so this one may seem a little tricky, so I'll try to explain it as best as I can. :)
So because they are consecutive odd numbers, that means they are odd numbers that are one after the other. This means each number is 2 apart from the next. So by using this, we know that there is a difference of 6 between the highest and lowest number. Now let's try and make an equation:
3o + 6 = 69
Now in order to get O by itself we have to subtract 6 from both sides:
3o = 63
Now we just have to divide by three on both sides:
o = 21
So now, we know that the lowest number is 21, but we have to add 2 to get 23, and then another 2 to get 25.
Hope this helps :)
Answer:
∠ ABC = 116°
Step-by-step explanation:
Since the angles are supplementary, they sum to 180° , that is
8x - 36 + 4x - 12 = 180
12x - 48 = 180 ( add 48 to both sides )
12x = 228 ( divide both sides by 12 )
x = 19
Then
∠ ABC = 8x - 36 = 8(19) - 36 = 152 - 36 = 116°
Answer:
x= 0 , 
, 
Step-by-step explanation:
Given, equation is ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D)
+ ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D)
= ![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D)
. →→→ (1)
Now, by cubing the equation on both sides, we get
( + )³ = ()³
⇒ (15x-1) + (13x+1) + 3×× ( + ) = 64 x.
⇒ 28x + 3×× () = 64x.
(since from (1), + = )
⇒ 12× × (![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
)= 36x.
⇒ 3x = ![\sqrt[3]{(15x-1)(13+1)(x)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2815x-1%29%2813%2B1%29%28x%29%7D)
.
Now, once again cubing on both sides, we get
(3x)³ = ()³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x = ; x =
therefore, solution is x= 0 , ,
Answer:
Andre has 4 pounds of Broccoli and 6 pounds of Zucchini.
Step-by-step explanation:
