The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
Answer:
0.
Step-by-step explanation:
Answer:
16.2
Step-by-step explanation:
Use the law of cos
c^2 = 8^2+10.4^2-2*8*10.4*cos(122.2 degrees)
=260.83
c = √260.83 = 16.15
Let the width be x, then the length is x + 12.
Area = length x width = x(x + 12) = 589
Solving the quadratic equation, we have that
x = 19 feet
i.e. the width is 19 feet.
