Answer:
The expected value of profit is -0.5125. This is expected loss as value is negative.
Step-by-step explanation:
We are given the following in the question:
P(winning) = 0.075
Thus,
P(Loosing) =
If we win we gain a profit of $5.50 and if we loose the lottery, we loose $1.
Thus, we can form the probability distribution in the following manner:
Event: Winning Loosing
Profit(x): +5.50 -1
P(x): 0.075 0.925
We have to calculate the expected value of the profit.
Thus, the expected value of profit is -0.5125. This is expected loss as value is negative.
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer: 20 pieces, 72 inches of ribbon
Step-by-step explanation: 6/1.5=4 4x5=20 6x12= 72 inches
Answer:
When x = 3
f(3) = 3 + 7 = 10
When x = -5
f(-5) = -5 + 7 = 2
please mark me the brainliest
Answer:
1. (A) Annuals only live for one year and will not return.
2. (B) when they appear between a character’s name and the character’s line
Step-by-step explanation:
Hope this helps!
