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3 years ago

Anyone know the middle question ?

Mathematics

2 answers:

Thepotemich [5.8K]3 years ago

6 0

Parrallel :)))))))))))

jeyben [28]3 years ago

4 0

Ab is obtuse acute to AD
DC is perpendicular parallel to AB

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The line with equation a + 4b = 0 coincides with the terminal side of an angle θ in standard position and cos θ > 0. What is

ankoles [38]

Answer:

Option A. -( $\frac{\sqrt{17}}{17}$ )

Step-by-step explanation:

Equation of a given line is a + 4b = 0 or b = - $\frac{1}{4}a$

This in the form of y = mx + b, which is slope-intercept form.

Here slope of the line is ( $-\frac{1}{4}$ ).

Or tanθ = $\frac{(-1)}{4}$

This line coincides with the terminal side of the angle in standard position where cosθ > 0

Since tanθ = $\frac{\text{Height}}{\text{Base}}$

and sinθ = $\frac{\text{height}}{\txt{Hypotenuse}}$

Hypotenuse = $\sqrt{\text{height}^{2}+\text{Base}^{2}}$

= $\sqrt{(1^{2}+4^{2})}$

= $\sqrt{17}$

Since tanθ is negative and cosθ > 0 that means θ lie in fourth quadrant.

Therefore, sinθ will be negative.

[ $\frac{-sin\theta}{+cos\theta}=-tan\theta$ ]

sinθ = - $\frac{1}{\sqrt{17}}$

= - $\frac{1}{\sqrt{17}}\times \frac{\sqrt{17} }{\sqrt{17}} = -\frac{\sqrt{17}}{17}$

Answer will be option A.

6 0

4 years ago

What is 100 x 0.95=_____

kifflom [539]

Answer: 95

Step-by-step explanation:

That’s the same as 0.95 of 100. That’s because 0.95 represents 0.95 and 100 represents 100, the of is the same as x. You can switch the two numbers and you can still get the same answer. So, 0.95 of 100 is 95.

5 0

3 years ago

In a class of 29 students, 19 are female and 14 have an a in the class. there are 8 students who are male and do not have an a i

vodomira [7]

Answer:

5/ 19 ≈ 0.26 = 26%

Step-by-step explanation:

given: student is female. there is a 100% chance that the student is female

probability we want = (favorable outcomes) / (total outcomes)

total outcomes = 19 because there are 19 female students and the student must be female

favorable outcomes = 19 - 14 = 5 females who do not have an A in the class

probability = 5/ 19 ≈ 0.26 = 26%

3 0

2 years ago

PLEASE HELP!! A car manufacturer does performance tests on its cars. During one test, a car starts from rest, and accelerates at

slega [8]

Answer:

0 ≤ t ≤ 25
16.348 seconds
310.0 meters

Step-by-step explanation:

a) Since these are production vehicles, we don't expect their top speed to be more than about 70 m/s, so the distance functions probably lose their validity after t = 25. Of course, t < 0 has no meaning in this case, so the suitable domain is about ...

0 ≤ t ≤ 25

Note that the domain for the second car would be 3 ≤ t ≤ 25.

b) The graph of this system shows the cars will both have driven the same distance after 16.348 seconds.

c) At that time, the cars will have driven 310.0 meters.

_____

<em>Non-graphical solution</em>

If you like, you can solve the equation for t:

d1 = d2

1.16t^2 = 1.74(t -3)^2

0 = 0.58t^2 -10.44t +15.66

t = (10.44 +√(10.44^2 -4(0.58)(15.66)))/(2(0.58)) = (10.44+8.524)/1.16

t = 16.348 . . . . time in seconds the cars are at the same distance

That distance is found using either equation for distance:

1.16t^2 = 1.16(16.348^2) = 310.036 . . . meters

6 0

4 years ago

74.362 to the nearest tenth

max2010maxim [7]

Answer:

73.4

Step-by-step explanation:

When they ask for the nearest tenth you check the hundreth, it its 5 or ore than you increase the tenth

8 0

3 years ago