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2 years ago

What is the factorization of the polynomial below-x^2 - 15x - 56

Mathematics

1 answer:

Andrej [43]2 years ago

3 0

Answer:

Step-by-step explanation:

This is more easily understood if you take out a common factor of -1

-1(x^2 + 15x + 56)

7*8 = 56

7 + 8 = 56

-1 (x +8)(x+7)

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Can someone help me with these questions

Varvara68 [4.7K]

Answer:

1.) can not be found

2.)V=11403.98

3.)

Step-by-step explanation:

volume = π r×r × H

r = Radius

H = height

π = 3.14

the first one does not have a radius so therefore we can NOT find the volume

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3 years ago

Write the rule for this pattern 1, 2, 4, 7, 11

rusak2 [61]

I'm not sure how to write the rule, but every time you add one more to the sum of the last two. First, you add 1, then 2, then 3. 1+1=2 2+2=4 4+3=7 7+4=11 and so on. I hope this helps!

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2 years ago

Hi I also need help with this please and thank you

OverLord2011 [107]

Answer:

Step-by-step explanation:

y=mx+b where m=slope and b=y intercept

m=(y2-y1)/(x2-x1)

m=(-2-4)/(2+1)

m=-2 so far we have the slope

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3 years ago

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coldgirl [10]

Answer:

x = 7

Step-by-step explanation:

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$\boxed{\green{x = 7}}$

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2 years ago

Read 2 more answers

Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

8 0

3 years ago

What is the factorization of the polynomial below-x^2 - 15x - 56​

What is the factorization of the polynomial below-x^2 - 15x - 56