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miv72 [106K]
3 years ago
5

(-0.25x -8)-(5.5x + 9.4) the simplified expression

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

=−5.75x−17.4

Step-by-step explanation:

=−0.25x−8+−1(5.5x+9.4)

=−0.25x+−8+−1(5.5x)+(−1)(9.4)

=−0.25x+−8+−5.5x+−9.4

another way >>>><<<<

=−0.25x+−8+−5.5x+−9.4

=(−0.25x+−5.5x)+(−8+−9.4)

=−5.75x+−17.4

Answer:

=−5.75x−17.4

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Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²
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Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

a^2-b^2=(a-b)(a+b)

Let us examine each of the given equation

\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}

From the above,

\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

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