Answer:
Is the question or is there more??
Step-by-step explanation:
(a)
since 13 is prime.
(b)
, and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so
.
(c)
; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with
.
(d)
; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so
.
Answer:
y=-2x-4
Step-by-step explanation:
4-9i÷-6i times both sides by 6i
6i(4-9i)÷6i(6i)
24i-54i²÷-36i²
24i-54(-1)÷-36(-1)
54+24i÷36 now reduce
9+4i÷6
I hope this helps!!
Answer:
5490
Step-by-step explanation:
you multiply every number by 6 and you will get the answer