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VARVARA [1.3K]
3 years ago
15

Find the surface are of the solid that is the intersection of the cylinders x^2+z^2=4 and y^2+z^2=4 in the first octant

Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

63892

Step-by-step explanation:

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3 years ago
Write the equation of the circle with center (2.-5) and a radius of 4. A) (x + 2)2 + (y - 3)2 - 4 B) (x - 2)2 + (y + 3)2 = 4 C (
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Answer:

Step-by-step explanation:

There must be an error in the question.

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