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VARVARA [1.3K]
3 years ago
15

Find the surface are of the solid that is the intersection of the cylinders x^2+z^2=4 and y^2+z^2=4 in the first octant

Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

63892

Step-by-step explanation:

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GIVING BRAINLIEST TO WHOEVER GETS IT RIGHT
ahrayia [7]

Answer:

x=3             x = -1

Step-by-step explanation:

f(x) = x^2 − 2x − 3

Set the function equal to zero

0 = x^2 − 2x − 3

Factor

What two numbers multiply to -3 and add to -2

-3 *1 = -3

-3+1 = -2

0 = (x-3)(x+1)

Using the zero product property

x-3 =0     x+1 =0

x=3             x = -1

7 0
3 years ago
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Find the value of s.<br>1s + 14 = 26​
belka [17]

Answer:

12

Step-by-step explanation:

1s + 14 = 26\\ 1s = 26 - 14 \\ 1s = 12 \\  \\ s =  \frac{12}{1}  \\  \\ s = 12

Thus, The Value Of S is 12

4 0
3 years ago
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If the point (-1/2, y) lies on the line whose equation is 2x - 3y = 6, what is the value of y?
salantis [7]
Plug in the known x value

2(-1/2)-3y=6
-1-3y=6
-3y=7
y=-7/3

Final answer: -7/3
4 0
3 years ago
Solve for x. Please help quick, it’s my last question for my test
Sladkaya [172]

Answer:

x = 9

Step-by-step explanation:

84 + (7x + 5) + (180 - (17x-1)) = 180

84 + 7x + 5 + (181 - 17x) = 180

270 + (-10x) = 180

90 = 10x

x = 9

3 0
3 years ago
!!!!!Help!!!!
Alja [10]
The correct answer is y=-13/10x+13 as it matches the graph

Hope this helped :)
7 0
3 years ago
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