The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:
S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.
1. Z=4 10-6
2 y= 6 48/8
3. Q= 13 12+1
6 m=15 11+4
7. 21 19+2
8. S=2 3-1
9. C=6 24/4
Answer:
23 should have been subtracted from, not added to, both sides of the equation.
Answer:
2(x+6)²
Step-by-step explanation:
