Joe bought g gollans of gasoline for $2.85 per gallon and c cans for oil for $3.15 per can

Carmen wants to join a gym. Gym A costs $26.76 plus an additional $4 for each visit. Gym B has no initial fee but costs $12.92 f

joja [24]

Answer:

After 3 visits both plans will cost the same.

Step-by-step explanation:

Gym A costs $26.76 plus an additional $4 for each visit.

Gym B has no initial fee but costs $12.92 for each visist.

The cost for gym A can be written as

C= $26.76 + 4(x) where x is the number of visits to the gym A

The cost for gym B can be written as

C= $12.92 (x) where x is the number of visits to the gym B

Both costs will be equal

12.92x= 26.76 +4x

12.92x-4x= 26.76

8.92x= 26.76

x= 26.76/8.92

x= 3

after 3 visits both plans will cost the same.

Check

12.92x= 26.76 +4x

12.92*3= 26.76 +12

38.76= 38.76

3 0

3 years ago

ΔEFI is dilated by a scale factor of one third with the center of dilation at point F. Then, it is reflected over line a to crea

timofeeve [1]

Answer:

The correct option is;

Segment FE over 3 = Segment FH

Segment FI over 3 = Segment FG, and

Segment EI over 3 = Segment HG

ΔEFI ~ ΔHFG

Step-by-step explanation:

The given transformations are'

ΔEFI is dilated by a scale factor of 1/3 and then it is reflected over line a

By dilation, we have

FH = 1/3×FE

FG = 1/3×FI

HG = 1/3×EI

Also by reflection over a line, the relative positions of the y-coordinates of the points remain the same while the x coordinates changes sign such that an upright mirror image of the dilated triangle is formed

Therefore, since we have;

$\dfrac{sin\alpha}{sin\beta } \ and \ \dfrac{sin\gamma}{sin\alpha }$ the same for both triangles, that is given the following relation;

FG/FH = (1/3×FI)/(1/3×FE) = FI/FE

Then, ΔEFI is similar to ΔHFG (triangle similarity requirement AAA)

Hence, the correct option is that the

Segment FE over 3 = Segment FH

Segment FI over 3 = Segment FG, and

Segment EI over 3 = Segment HG

ΔEFI ~ ΔHFG.

4 0

3 years ago

Read 2 more answers

) A camera shop charges $3.99 for an enlargement of

Keith_Richards [23]

Answer:

Total Cost $C = \$3.99 e+\$1.49$

Step-by-step explanation:

Given:

Charges for an enlargement of 1 photograph = $\$3.99$

Delivery charge per order = $\$1.49$

Let number of enlargements of photograph in an order be $e$

We need to find the Total cost C of an order.

So the Total Cost would be equal to Charges for an enlargement of 1 photograph $\times$ number of enlargements of photograph in an order plus Delivery charge per order.