The dimensions of the rectangle will be 6 inches and 12 inches.
<h3>What is the area of the rectangle?</h3>
Let L be the length and W be the width of the rectangle.
Then the area of the rectangle will be
Area of the rectangle = L × W square units
The length of a rectangular poster is 9 more inches than half its width.
L = W/2 + 9
The area of the poster is 72 square inches. Then we have
72 = L × W
72 = (W/2 + 9) × W
144 = (W + 18) × W
144 = W² + 18W
W² + 18W - 144 = 0
Then the factor of the equation will be
W² + 18W - 144 = 0
W² + 24W - 6W - 144 = 0
W(W + 24) - 6(W + 24) = 0
(W + 24)(W - 6) = 0
W = -24, 6
The width of the rectangle is 6 inches. Then the length of the rectangle will be
L = 6/2 + 9
L = 3 + 9
L = 12 inches
The dimensions of the rectangle will be 6 inches and 12 inches.
More about the area of the rectangle link is given below.
brainly.com/question/20693059
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In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.
Answer:7.15
Step-by-step explanation: You multiply it
