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Temka [501]
3 years ago
11

Find the area of the shaded region. Show your work please

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
So if the formula is A=(pi)r^2, find the area of the entire circle:
A=(pi)(13^2)=530.66cm
then find the area of the little circle:
A=(pi)(3^2)= 28.26cm
then subtract the little circle from the big circle:
530.66cm-28.26cm= 502.4cm
and there you go. Hope this helps!

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Please Answer Attachment Below Thanks
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Answer:

Step-by-step explanation:

The interior angles of a heptagon add up to 5*180 = 900

So

x + 143 + 116 + 135 + 135 + 116 + 155 = 900     Add up the known angles

x + 800 = 900                                                   Subtract 800 from both sides

x + 800 - 800 = 900 - 800                              Combine

x = 100

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3 years ago
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Answer:

{10}^{ - 14}

Step-by-step explanation:

\huge\frac{ {10}^{ - 9} }{ {10}^{5} }  \\  \\  \huge =  {10}^{ - 9}  \times  {10}^{ - 5}  \\  \\  \huge =  {10}^{ - 9  + ( - 5)}  \\  \\ \huge =  {10}^{ - 9 - 5}  \\  \\  \huge \orange {=  {10}^{ - 14}}

7 0
3 years ago
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maria [59]

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6 0
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Step-by-step explanation:

6 0
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What is an equation for a sine curve with amplitude 2, and period 4pi radians ?
Nezavi [6.7K]
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude  and  n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)

The correct answer is option D. y = 2 sin (θ/2)
===========================================

<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude  and  n = 2π/period
<span>amplitude = 5  , period = 2π/n = 2π/2 = π
</span>

The correct answer is option B. Period: pi radians: Amplitude:5

============================================================
3. tan (2π/3) = tan 120° = -√3 
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3

The correct answer is C. -sqrt3

=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
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150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
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The correct answer is <span>B.-sqrt3/3</span>
8 0
3 years ago
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