What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
Answer:
Probability = 0
Step-by-step explanation:
If something happening is impossible, it's probability of occurring is also 0.
A deck of cards only contains 4 jacks.
Thus you can never get 6 jacks out of the deck without replacing the selected card each time.
Since we are not replacing the cards once we pick them, this event is impossible to occur.
Given
gas prices are now $3.75 and it up 10% from 6 months ago.
Find out how much were gas prices 6 months ago.
To proof
gas prices now = $3.75
let the gas price 6 month ago = x
gas price now is rise up 10% from 6 months ago
First write 10% in simpler form
= 0.1
Now the equation becomes
0.1x + x = 3.75
1.1x = 3.75
x = 3.41 (approx)
Thus gas prices 6 months ago be $ 3.41 (approx )
Hence proved
Answer:
6=2 , 12=4, 15=5, 24=8
Step-by-step explanation:
The pairs of prime numbers (a,b) between 1 and 10 inclusive such that a^b * b^a+1 is prime are
<h3>How to determine the pairs of numbers?</h3>
The expression that is a prime number is given as:
a^b * b^a + 1
The boundary or range of numbers of a and b is not given.
So, we make use of numbers between 1 and 10
i.e. 1 ≤ a ≤ 10 and 1 ≤ b ≤ 10
Using the above range, we have the following program to determine the pairs of prime numbers (a, b).
for a in range(1,11):
for b in range(1,11):
num = (a* *b) * (b* *a) + 1
flg = False
if num > 1:
for i in ra nge(2, num):
if (num % i) == 0:
flg = True
break
if not flg:
print(str(a)+","+str(b))
The output of the above program is:
(1,1), (1,2), (1,4), (1,6), (1,10), (2,1), (2,2), (2,3), (2,4), (3,2), (4,1), (4,2), (4,4) and (4,6)
The above represent all pairs of prime numbers (a,b) such that a^b * b^a+1 is prime
Read more about prime numbers at:
brainly.com/question/25710806
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