2 years ago

Which is the solution to the inequality? 1/4 + x < 5/8

1 answer:

7 0

X < 3/8 would be correct I think, you are solving for the system of inequalities, right? tell me if you need a different answer, i'll try to help to the best of my abilities

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Dave bought 8 more Xbox games than Kevin Dave bought 12 games. how many games did Kevin buy

Nadusha1986 [10]

Answer: 12 -8 = 4

Step-by-step explanation:

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2 years ago

Factor the following polynomial completely 6x^5-30x^4-84x^3

Andrei [34K]

Answer:

6x^3(x+2)(x-7)

Step-by-step explanation:

1st step: factor out common term, 6x^3(x^2 - 5x - 14)

2nd step: Factor x^2 - 5x - 14, (x + 2)(x - 7)

3rd step: simplify, 6x^3(x+2)(x-7)

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2 years ago

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Alexeev081 [22]

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3 years ago

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Jeff needs to create a password for his E-mail account. The password must have four letters. How many different passwords can he

Flura [38]

Answer:

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Step-by-step explanation:

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2 years ago

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Please help me Algebra 1

Oduvanchick [21]

Answer:

a. $\sqrt{x^n}$ = $x^\frac{n}{2}$

b. $\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

Step-by-step explanation:

a) When n is even, then it is divisible by 2. Because of this, you can write:

$\sqrt{x^n} = (x^n)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{n}{2}$

b) When n is odd, then n - 1 is even. This would make it divisible by 2, and there would be a remainder of 1, so we can write:

$\sqrt{x^n} = (x^n^-^1^+^1) ^\frac{1}{2}$

$\sqrt{x^n} = (x^n^-^1$ × $x)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}$ × $x^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

8 0

2 years ago

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